Team Teach 3.2 Homework and Popcorn Hacks

3.2 TEAM TEACH Monday

Popcorn hacks + Homework

# Abstracting keys and assigning numbers 1, 2, and 3 to them
fruit_dict = {1: "bananas", 2: "apples", 3: "pears"}
# Creating a corresponding dictionary for their values
fruit_values = {"bananas": 1, "apples": 2, "pears": 3}
# Accessing the value using the key (e.g., key 1 for bananas)
key = 1  # You can change this to 2 or 3 for other fruits
# Output the corresponding fruit and its value
fruit = fruit_dict[key]  # This gives us the fruit name
value = fruit_values[fruit]  # This gives us the value associated with the fruit

print(f"The fruit for key {key} is {fruit} and its value is {value}.")

The fruit for key 1 is bananas and its value is 1.

Popcorn hack 2

# Simple Command-Line Calculator in Python

# Get user input
first_number = float(input("Please Enter the First Number Here: "))
second_number = float(input("Please Enter the Second Number Here: "))
math_function = input("Please Enter the operation (+, -, *, /): ")

# Perform the calculation based on the math_function input
if math_function == "+":
    result = first_number + second_number
elif math_function == "-":
    result = first_number - second_number
elif math_function == "*":
    result = first_number * second_number
elif math_function == "/":
    # Check for division by zero
    if second_number == 0:
        result = "Error: Division by zero is undefined."
    else:
        result = first_number / second_number
else:
    result = "Invalid operation!"

# Output the result
print("Result:", result)

Result: 4.0

Popcorn Hack 3

def repeat_strings(strings, n):
    return [string * n for string in strings]  # Using list comprehension to repeat each string `n` times

# Test the function
string_list = ["apple", "banana", "orange"]
repeated_strings = repeat_strings(string_list, 2)
print(repeated_strings)

['appleapple', 'bananabanana', 'orangeorange']

Popcorn hack 4

def sets_have_common_elements(set1, set2):
    return not set1.isdisjoint(set2)  

print(sets_have_common_elements({1, 2, 3}, {3, 4}))  # Output: True
print(sets_have_common_elements({1, 2, 3}, {4, 5}))  # Output: False

True
False

Homework

Part 1

profile = {
    "name": "Alex Rubio",  
    "age": 15,          
    "city": "San diego", 
    "favorite_color": "purple"  
}
print(profile)

{'name': 'Alex Rubio', 'age': 15, 'city': 'San diego', 'favorite_color': 'purple'}

Part 2

# Part 2: Create a hobbies list
hobbies = ["reading", "cycling", "coding"] 
print(hobbies)

['reading', 'cycling', 'coding']

Part 3

# Part 3: Add hobbies to the profile dictionary
profile["hobbies"] = hobbies
print(profile)

{'name': 'Alex Rubio', 'age': 15, 'city': 'San diego', 'favorite_color': 'purple', 'hobbies': ['reading', 'cycling', 'coding']}

Part 4

# Part 4: Check availability of a hobby
hobby_of_choice = "cycling"  # Choose one of the hobbies
has_hobby = True  # Example: Set to True if it's available today

# Print availability of the hobby
print(f"Is {hobby_of_choice} available today? {has_hobby}")

Is cycling available today? True

Part 5

# Part 5: Count total number of hobbies
total_hobbies = len(hobbies)
print(f"I have {total_hobbies} hobbies.")

I have 3 hobbies.

Part 6

# Part 6: Create a tuple for favorite hobbies
favorite_hobbies = ("reading", "coding")  # Example: Two favorite hobbies
print(favorite_hobbies)

('reading', 'coding')

Part 7

# Part 7: Create a set of skills
skills = {"programming", "public speaking", "graphic design"}  # Example skills
print(skills)

{'programming', 'graphic design', 'public speaking'}

Part 8

# Part 8: Create a variable for new skill
new_skill = None  # You haven't decided yet
print(new_skill)

None

Part 9

# Part 9: Calculate the total profile cost
# Each hobby costs $5, and each skill costs $10
hobby_cost = 5
skill_cost = 10

total_cost = (total_hobbies * hobby_cost) + (len(skills) * skill_cost)
print(f"Total cost to pursue hobbies and develop skills: ${total_cost:.2f}")

Total cost to pursue hobbies and develop skills: $45.00